0.1x^2-13x+3=0

Solution for 0.1x^2-13x+3=0 equation:

0.1x^2-13x+3=0

a = 0.1; b = -13; c = +3;
Δ = b2-4ac
Δ = -132-4·0.1·3
Δ = 167.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{167.8}}{2*0.1}=\frac{13-\sqrt{167.8}}{0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{167.8}}{2*0.1}=\frac{13+\sqrt{167.8}}{0.2}
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